Answer:
![D =(P)/(\pi X^2)](https://img.qammunity.org/2021/formulas/mathematics/college/ckkmu6px80axyftysr8k20885rj2yatytz.png)
And solving for the radius we got:
![X = \sqrt{(P)/(\pi D)}](https://img.qammunity.org/2021/formulas/mathematics/college/90ap5iumszstl68na83yd7z3j96tmt7l6n.png)
And replacing the data given we got:
![X = \sqrt{(480 (people)/(km^2))/(\pi *20000 people)}= 0.0874Km](https://img.qammunity.org/2021/formulas/mathematics/college/83imnno2h7n1bq4nvn6h9wvl3j9mptjaca.png)
And this value converted to meters is
![X = 87.40 m](https://img.qammunity.org/2021/formulas/mathematics/college/eykx28rx7lk20w4fbsn8oj5ku6guyarybo.png)
Explanation:
For this case we know the population size
and we also know the population density
![D = 480 (people)/(km^2)](https://img.qammunity.org/2021/formulas/mathematics/college/f4udjrypxqxfehlpbtpnp1uc8ln2ca09sy.png)
We can assume that the area is a circle. We also know that the formula for the population density is given by:
![D= (P)/(A)](https://img.qammunity.org/2021/formulas/mathematics/college/68s4saeveo9h3el18e0mffpq2kvq90671n.png)
Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:
![A = \pi X^2](https://img.qammunity.org/2021/formulas/mathematics/college/cq7m7515gsno6huxde7fdvgs4ry4rw5idg.png)
With X the radius of the circle
And then the populationd density become:
![D =(P)/(\pi X^2)](https://img.qammunity.org/2021/formulas/mathematics/college/ckkmu6px80axyftysr8k20885rj2yatytz.png)
And solving for the radius we got:
![X = \sqrt{(P)/(\pi D)}](https://img.qammunity.org/2021/formulas/mathematics/college/90ap5iumszstl68na83yd7z3j96tmt7l6n.png)
And replacing the data given we got:
![X = \sqrt{(480 (people)/(km^2))/(\pi *20000 people)}= 0.0874Km](https://img.qammunity.org/2021/formulas/mathematics/college/83imnno2h7n1bq4nvn6h9wvl3j9mptjaca.png)
And this value converted to meters is
![X = 87.40 m](https://img.qammunity.org/2021/formulas/mathematics/college/eykx28rx7lk20w4fbsn8oj5ku6guyarybo.png)