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A roller coaster car of mass m = 300 kg is released from rest at the top of a 60 m high hill (position A), and rolls with a negligible friction down the hill, through a circular loop of radius 20 m (Positions B,C,and D) and along a horizontal track

2 Answers

5 votes

Final answer:

The physics questions involve applying energy conservation and centripetal force principles to calculate speeds, accelerations, and angular momentum of a roller coaster ride.

Step-by-step explanation:

The student's question is about applying the principles of energy conservation and centripetal force to a roller coaster scenario in a physics context. The mass of the roller coaster and its position on the track are given, and the student is expected to calculate various physical quantities like speed, acceleration, and angular momentum related to the roller coaster's motion through a vertical loop. To solve these problems, one would use the conservation of mechanical energy for scenarios without friction, and for circular motion, the concept of centripetal acceleration will be necessary.

For instance, to find the minimum speed at the top of a loop, the student must ensure that the centripetal force is enough to keep the roller coaster in circular motion without falling. The calculation would involve the gravitational potential energy at the initial height, the kinetic energy at the top of the loop, and maybe the normal force acting on the roller coaster at different points if friction is negligible.

User HydTechie
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3.9k points
7 votes

Answer:

The principle of conservation of energy and angular momentum

Step-by-step explanation:

At point A, the car experienced maximum of potential energy

As it moves down the hill, the potential energy decreases while the kinetic energy increases.

The maximum kinetic energy of the car is needed for the attainment of enough centripetal force to help the car move through the loop without falling .

User Chad Steele
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3.7k points