Question

How much energy will a sample of copper alloy ( 63.0 g) lose if it is cooled from 48.0° to 23.0°C ?

463 J
365 J
729 J
623 J

Answer 1

Heat lost would be 606.375J

Step-by-step explanation:

Mass = 63.0g

T1 = 48°C

T2 = 23°C

Specific heat capacity of copper (c) = 0.385J/g°C

Q = Mc∇T

Q = Mc(T₂ - T₁)

Q = 63 * 0.385 * (23 - 48)

Q = 24.255 * -25

Q = -606.375J

The heat lost would be 606.375J

Answer 2

623 J

Step-by-step explanation:

The quantity of heat released by the sample is quantified with the help of the First Law of Thermodynamics:

`Q = (63\,g)\cdot \left(0.390\,(J)/(g\cdot ^(\circ)C) \right)\cdot (23^(\circ)C-48^(\circ)C)`

`Q = -614.25\,J`

The best approximation is 623 J.