117k views
1 vote
In ΔJKL, the measure of ∠L=90°, LJ = 72 feet, and JK = 93 feet. Find the measure of ∠J to the nearest degree.

User Radex
by
3.2k points

2 Answers

3 votes

Answer:

39

Explanation:

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\cos J = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{72}{93}

cosJ=

hypotenuse

adjacent

=

93

72

\cos J = \frac{72}{93}

cosJ=

93

72

J=\cos^{-1}(\frac{72}{93})

J=cos

−1

(

93

72

)

J=39.268\approx 39^{\circ}

J=39.268≈39

Type into calculator and round to the nearest degree.

J

K

L

72

93

(adjacent to ∠J)

(opp. of ∠J)

(hypotenuse)

39°

User Corin
by
3.5k points
2 votes

Answer:

39°

Explanation:

User Viktor Arsanov
by
3.4k points