Answer:
about 5.9%
Explanation:
We assume that the original amount of Pb-210 present at death decays at the given rate. The fraction (f) remaining is multiplied by 1/2 every 22 years, so can be modeled by ...
f = (1/2)^(t/22) . . . . . where t is in years after death
Then, for t=90, the remaining fraction is ...
f = (1/2)^(90/22) ≈ 0.05868 ≈ 5.9%