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How much energy would be absorbed as heat by 25 g of iron when heated from 295 K to 306 K?

1 Answer

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Answer:

1.2 × 10² J

Step-by-step explanation:

Given data

  • Mass of iron (m): 25 g
  • Initial temperature: 295 K
  • Final temperature: 306 K

The amount of heat (Q) that a substance absorbs depends on its specific heat capacity (c), which is the amount of heat energy required to raise the temperature of a substance per unit of mass. It can be calculated through the following expression. (cFe = 0.444 J/g.K)


Q = c * m * (T_f-T_i) \\Q = (0.444J)/(g.K) * 25g * (306K-295K)\\Q = 1.2 * 10^(2) J

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