3.6k views
4 votes
Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? Check all that apply.

User Lightyeare
by
4.1k points

2 Answers

5 votes

Answer:a quadratic equation has no real number solutions than the discriminant is less than zero

D < 0

(b^2 -4ac) < 0

(9 -4(-1*c) < 0

(9+4c) < 0

4c < -9

c < -9/4

Explanation:

User Gergan Zhekov
by
3.4k points
4 votes

Answer:

c=x2−3x

Explanation:

Let's solve for c.

−x2+3x+c=0

Step 1: Add x^2 to both sides.

−x2+c+3x+x2=0+x2

c+3x=x2

Step 2: Add -3x to both sides.

c+3x+−3x=x2+−3x

c=x2−3x

Answer:

c=x2−3x

User Tchaps
by
3.1k points