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Find all relative maximum and minimums of f(x) =2x^3-3x^2-12x+5 Explain your steps in detail.

User MhKarami
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1 Answer

11 votes

Answer:

The relative minimum is (3,-4) and the relative maximum is (-2,1)

Explanation:

The first step is to take the derivative of f(x)

By using the power rule which is d/dx x^n=nx^n-1 you will find that the derivative is 6x^2-6x-12

The next step is to set the derivative = to 0 and by doing that you will obtain x being equaled to -2 and 3

Put -2 and 3 on a sign chart and determine the behavior for both of those functions

The outcome of your sign chart should be + - + because of the odd multimplicity of (x-3) and (x+2).

The next step is to find the f(x) values or y values of your two points

By plugging in 3 into f(x), you get -4 and by plugging in -2 into f(x) you get 1

Since there was interval given, I cannot find the absolute extremas of this function.

User Nicholas Rishel
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