Question

1000 g of water (specific heat = 4.184 J/(g *C)) is heated from freezing (0°C) to boiling (100°C). How much heat energy is required to

achieve this temperature change? ( gotta show work too)

Answer 1

Answer: The heat energy required to achieve this temperature change is 418400 Joules

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed= ?

m= mass of water = 1000 g

c = specific heat capacity =
`4.184J/g^0C`

Initial temperature of the water =
`T_i` = 0°C

Final temperature of the water =
`T_f` = 100°C

Change in temperature ,
`\Delta T=T_f-T_i=(100-0)^0C=100^0C`

Putting in the values, we get:

`Q=1000g* 4.184J/g^0C* 100^0C`

`Q=418400J`

The heat energy required to achieve this temperature change is 418400 Joules