Question

Calculate the molarity of 6.631 g NANO3 in 100.0 mL of solution


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Answer 1

Step-by-step explanation:

Mole weight of NaNO3 ====> ~~ 85 gm

6.631 / 85 = # moles in .1 liter

6.631/85 / (.1) = .78 M

Answer 2

0.7802 M

Step-by-step explanation:

Data:

• V (volume) = 100.0 mL → V = 0.1000 L
• m (mass) = 6.631 g → n = 0.07802 mol

Wanted:

• M (Molarity)

Equation:

M =
`(mol)/(L)`

Solution:

1. Convert mL to L:

• V = 100.0 mL x
  `(1 L)/(1000 mL)` = 0.1000 L

2. Convert g to mol:

• n =
  `(6.631 g)/(84.9947 g/mol)` = 0.07802 mol

3. Molarity Equation:

• M =
  `(0.07802 mol)/(0.1000 L)` = 0.7802 M