Question

Given circle E with diameter CD and radius EA. AB is tangent to E at A. if AD = 15 and EC = 14, solve for AC.

Answer 1

AC ≈ 23.6 units

Explanation:

m∠CAD = 90°

CD = 2×14 = 28 , AD = 15

CD² = AD² + AC² ⇒ AC² = CD² - AD²

AC² = 28² - 15² = ( 28 - 15 )( 28 + 15 ) = 13 × 43 = 559

AC ≈ 23.6