Question

Finish the steps below to write a quadratic function for the parabola shown. Use the vertex form, f(x) = a(x – h)2 + k, and substitute in the values for h and k. f(x) = a(x – 5)2 + 3 Use another point and substitute in values for x and f(x). Solve for a. 5 = a(6 – 5)2 + 3 Write the function, using the values for h, k, and a. The function is f(x) = (x – )2 + .

Answer 1

Answer:f(x) = a(x – h)² + k

we know the vertex v(5,3)

substitute in the values for h and k

f(x) = a(x – 5)² + 3

Use another point and substitute in values for x and f(x).

for the point (6,5)

Solve for a.

5 = a(6 – 5)2 + 3-------------- > 5=a+3-------------> a=2

The function is f(x)=a(x – h)2 + k-------- > 2(x – 5)² + 3

f(x)= 2(x – 5)² + 3-------- > 2[x²-10x+25]+3=2x²-20x+50+3=2x²-20x+53

f(x)=2x²-20x+53

the answer is f(x)= 2(x – 5)² + 3----------------- > (f(x)=2x²-20x+53)

Explanation:

Answer 2

yes, the answers are as follow:

first 2

second 5

last 3

forming f(x) = 2(x-5)^2 + 3

Explanation:

got it right in edg 2020 hope this is of help :)