Question

Please I need help for number 1 and number 2 only!!! Please help!!!

Answer 1

SA = pi × r × l + pi × r²

SA = pi × r × (l + r)

1. SA = 3.14 × 6 × (10 + 6)

= 301.44 units²

Volume = 3.14 × 6² × 8

= 904.32 units³

2. l² = 5² + 12²

l² = 169

l = 13

SA = 3.14 × 5 × (13 + 5)

= 282.6 units²

Volume = 3.14 × 5² × 12

= 942 units³

3. Radius = 5/2 = 2.5

Lateral SA = pi × r × l

3.14 × 2.5 × 6.5

= 51.025 units²

Answer 2

1. A = 96π units squared

V = 96π units cubed

2. A = 90π units squared

V = 100π units cubed

Explanation:

1. We need to find the surface area first. Use the given formula and the given dimensions:

A = πr² + πrl, where r is the radius and l is the slant height

r = 6

l = 10

Plug these values in:

A = πr² + πrl = π * 6² + π * 6 * 10 = 36π + 60π = 96π units squared

The volume is denoted by: V = (1/3)πr²h, where r is the radius and h is the height. We know r = 6 and h = 8, so:

V = (1/3)πr²h

V = (1/3)π * 6² * 8 = 96π units cubed

2. Again, use the surface area formula: A = πr² + πrl and the given dimensions. We're given that the radius is r = 5 and the height is 12, so by the Pythagorean Theorem, the slant height is √(5² + 12²) = √13² = 13. Then:

A = πr² + πrl

A = π * 5² + π * 5 * 13 = 90π units squared

Now for volume:

V = (1/3)πr²h

V = (1/3)π * 5² * 12 = 100π units cubed