Question

Part 1

An engine absorbs 1969 J from a hot reservoir and expels 1223 J to a cold reservoir in each cycle. What is the engine’s efficiency? Answer with an efficiency in decimal form.


Part 2
How much work is done in each cycle?
Answer in units of J.


Part 3
What is the mechanical power output of the engine if each cycle lasts for 0.345 s?
Answer in units of kW

Answer 1

Part 1: 0.3789

Part 2: 746 J

Part 3: 2.162 kW

Step-by-step explanation:

Part 1:

Eff=
`1-(1223)/(1969)`

Eff= 0.378873 ≈ 0/3789

Part 2:

W= 0.3789(1969)

W= 746 J

Part 3:

`Power=(W)/(t)`

`Power= (746)/(0.345)`

Power= 2162.3188 Watts

2162.3188 W-----> 2.162 kW