Question

What is the critical angle for glass which has a refractive index of n=1.6?

Answer 1

Answer:38.7

Step-by-step explanation:

Refractive index=n=1.6

Critical angle=c

n=1/sinc

1.6=1/sinc

Cross multiply

1.6xsinc=1

Divide both sides by 1.6

(1.6xsinc)/1.6=1/1.6

sinc=1/1.6

sinc=0.625

c=sin(inverse)(0.625)

c=38.7

Critical angle is 38.7°