Question

a quantity of gas has a volume of 400.0 mL when confined under a pressure of 600.0mm Hg. what will be the new volume of the gas if the pressure is reduced to 200.0mm Hg at constant temperature?

Answer 1

1200 mL

Step-by-step explanation:

Given data

• Initial pressure (P₁): 600.0 mmHg

• Initial volume (V₁): 400.0 mL

• Final pressure (P₂): 200.0 mmHg

• Final volume (V₂): ?

For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.

`P_1 * V_1 = P_2 * V_2\\V_2 = (P_1 * V_1)/(P_2) = (600.0mmHg * 400.0mL)/(200.0mmHg)=1200 mL`