Question

Solve the system of inequalities:
6y≥42
4y+12≤0

Answer 1

no solution

Explanation:

6y≥42

Divide each side by 6

6y/6≥42/6

y≥7

Then solve the second one

4y+12≤0

Subtract 12 from each side

4y+12-12≤0-12

4y ≤-12

Divide each side by 4

4y/4 ≤-12/4

y ≤-3

There is no solution since there is no overlap