Question

Point A has coordinates (0,4).

Point B has coordinates (1,6).
Point C has coordinates (2,0).
Find an equation of the line that passes through C and is perpendicular to AB.
equation needs to be in the form ax+by= c
a and b need to he integers ASAP PLS HELP

Answer 1

x - 6y - 2 = 0

Explanation:

Let “m” be the slope of line AB

and “a” be the slope of the line that passes through C and is perpendicular to AB

Then

`m = (6-0)/(1-2) =-6`

The second line is perpendicular to AB

then

m × a = -1

then

-6 × a = -1

then

`a=(1)/(6)`

C(2,0) lies on the line of equation y=ax+b

⇔ C(2,0) lies on the line of equation y=(1/6)x+b

⇔ 0 = (1/6)×2 + b

Then b= -1/3

Therefore Our equation is :

y = (1/6)x - 1/3

⇔ 6y = x - 2

⇔ x - 6y - 2 = 0