Question

Francine bought a TV that is 31 inches tall and 57 inches wide. She is going to mount it on the wall in her living room.

The wall is 8 feet wide and 9 feet tall.
How many square inches of the wall will not be covered by the TV once it is mounted?​

Answer 1

To determine the area of the wall not covered by the TV, first calculate the area of both the wall and the TV in square inches, then subtract the TV's area from the wall's area. The uncovered area is 8,601 square inches.

Step-by-step explanation:

The student is asking how many square inches of the wall will not be covered by the TV once it is mounted. To solve this, first, we need to calculate the area of the wall in inches, since we're given the dimensions in feet: 8 feet wide is 96 inches (8 x 12) and 9 feet tall is 108 inches (9 x 12). Therefore, the wall has an area of 96 inches x 108 inches, which equals 10,368 square inches.

Next, we calculate the area of the TV: 31 inches tall by 57 inches wide gives us an area of 1,767 square inches (31 x 57). To find the area of the wall that will not be covered by the TV, we subtract the area of the TV from the area of the wall, which gives us 10,368 square inches - 1,767 square inches = 8,601 square inches. This is the area of the wall that will not be covered by the TV.

Answer 2

the tv would actually be too big for the wall, or cover all of that wall and then some.

Step-by-step explanation:

so the formula for this is going to be lxw

notice the units are different. this is an easy fix. either divide the inches by 12 or multiply the ft by 12. (12 inches in a foot)

tv= 31in x 57in= 1,767 in2

wall= 8ftx9ft= 72 ft2

if the wall is 72ft2, then it would be 864in2

(72in2 x 12= 864in2)

if the tv is 1,767 in2 and the wall is 864in2 ; the tv would actually be too big for the wall; or cover all of that wall and then some.