Question

8. Calculate the area of rectangle A, the area of rectangle

B, and the area of the largest rectangle.
Then, using a fraction, compare the area of rectangle A
with the area of the largest rectangle. In other words,
the area of rectangle A is what fraction of the area of the
largest rectangle? Express this fraction in lowest terms.
2x on the side and the bottom of rectangle A and 2x on the side of rectangle B and x on the top.

Answer 1

A: 4x^2

B: 2x^2

largest: 4x^2

fraction: 1

Explanation:

a) The area of a rectangle is the product of length and width:

areaA = (2x)(2x) = 4x^2

b) areaB = (2x)(x) = 2x^2

c) The area of the largest rectangle is areaA = 4x^2

d) The ratio of areaA to the largest rectangle is ...

(4x^2)/(4x^2) = 1

Area A is 1 of the area of the largest rectangle.

Answer 2

• A: 4x^2
• B: 2x^2
• largest: 4x^2
• fraction: 1

Explanation:

a) The area of a rectangle is the product of length and width:

areaA = (2x)(2x) = 4x^2

b) areaB = (2x)(x) = 2x^2

c) The area of the largest rectangle is areaA = 4x^2

d) The ratio of areaA to the largest rectangle is ...

(4x^2)/(4x^2) = 1

Area A is 1 of the area of the largest rectangle.