Question

What number to be added to each of the number 6,16,36 and 76 to be in proportion?​

Answer 1

`\pink{ \pmb{SOLUTION:-}}`

Here,

• Let x must be added.

`\displaystyle{ (6 + x)/(16 + x) = (36 + x)/(76 + x) }`

`(6 + x)(76 + x) = (36 + x)(16 + x)`

`456 + 6x + 76x + {x}^(2) = 576 + 36x + 16x + {x}^(2)`

`82x + 456 = 576 + 52x`

`82x - 52x = 576 - 456`

`30x = 120`

`\displaystyle{x = (120)/(30) }`

`{ \rightarrow{ \pmb{x = 4}}}`