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5 votes
A pyramid has a square base with sides 100 feet long. The original height was 75 feet.

but the top part of the pyramid, which was 15 feet in height, was cut off.
What percent of the original volume remains?​

User Chris Rice
by
5.6k points

2 Answers

6 votes

Answer:

99.2%

Explanation:

Ratio of volumes = (Ratio of sides)³

Ratio of volumes = (15/75)³

Ratio of volumes = 1/125

1/125 × 100 = 0.8% was cut off

100 - 0.8 = 99.2% remains

User Thomas Lielacher
by
5.7k points
6 votes

Explanation:

Step 1: Find the volume of the original pyramid


V = a^2*(h)/(3)


V=(100)^2*(75)/(3)


V=10000*25


V=250000

Step 2: Find the volume of the cut off


V=(20)^2*(15)/(3)


V = 400*5


V=2000

Step 3: Find the percent that still remains


250000-2000


248000


248000 / 250000


0.992*100


99.2

Answer: 99.2%

User Bakasan
by
6.3k points