Question

An excess of nitrogen reacts with 32.6 grams of hydrogen. What volume of ammonia is produced at STP? N2(g) + 3H2(g)  2NH3(g)?​

Answer 1

to find:

the volume of ammonia produced at STP.

solution:

Mass of hydrogen is 32.6g

Molar mass of H2 = 2 g/mol

Moles of H = 32.6g/2g/mol = 16.3mol

N2(g) + 3H2(g) —-> 2NH3(g)

The Mole ratio of H to NH3 is 3 : 1

32.6 mole of H = 1/3 x 16.3= 10.87 mol = 5.43mol

Moles of NH3 = 5.43mol

At STP moles = volume/molar volume, but molar volume = 22.4L/mol

Moles = volume/molar volume, volume = moles X molar volume

Volume = 5.43 mol x 22.4L/mol

= 121.63 L

Volume of NH3 = 121.63L