Question

A 20.0 mL sample of hydrochloric acid was neutralized with 58.4 mL of 0.250 M NaOH, in a titration.

a. Write the balanced chemical equation for the reaction,
b. What is the concentration of the hydrochloric acid?

Answer 1

M= 0.73

Step-by-step explanation:

a)

HCl + NaOH -> NaCl + H2O

b)

M= mol solute/ L solution

mol NaOH = M* L solution mol NaOH= 0.250 M * 0.0584L =

0.0146 mol NaOH

mol NaOH= mol HCl

M= mol HCl/ L solution

M= 0.0146 mol HCl/0.02 L M= 0.73