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Three beads are picked from a bag containing 5 white beads and 4 yellow beads. Note that each bead is put back before the next is selected. Find the probability of picking one yellow and two white beads.

User Ololoking
by
6.8k points

2 Answers

6 votes

Answer:


(100)/(729)

Explanation:

For this, you need to firstly make the 3 beads a fraction.

Add 5 and 4.

5+4=9

The denominator will be 9 for each fraction.


(4)/(9)×
(5)/(9)×
(5)/(9)

Now multiply.


(100)/(729)

You cannot simplify it further so it will stay as the fraction.

User Anton Danilov
by
7.2k points
6 votes

Answer:

100/729

Explanation:

The probability of picking a yellow bead is 4/9, since there are 4 yellow beads in the bag and 9 beads in total. The probability of picking white beads both times is 5/9, for the same reason. Therefore, the probability of these events happening is 4/9*5/9*5/9=100/729. Hope this helps!

User Ccrez
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7.6k points