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A 10 kg object is travelling at 2.0 m/s. After 30 seconds the object's speed becomes 3.0

m/s. What is the work done on it, in J?

2 Answers

3 votes

Answer:7350 joules

Step-by-step explanation:

Mass(m)=10kg

Initial velocity(u)=2m/s

Final velocity(v)=3m/s

Time(t)=30s

Acceleration horizontally=a

Acceleration due to gravity(g)=9.8m/s^2

d=(u+v)/2 x t

d=(2+3)/2 x30

d=5/2 x 30

d=(5x30)/2

d=150/2

d=75

Force=mass x acceleration due to gravity

Force=10x9.8

Force=98N

Work=force x distance

Work=98 x 75

Work=7350J

User AShah
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3.9k points
3 votes
I think this might be the answer, if it is I’ll be very surprised =/
A 10 kg object is travelling at 2.0 m/s. After 30 seconds the object's speed becomes-example-1
User WhiteEleven
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4.6k points