How many grams of Calcium are present in 33.0 g of Calcium Fluoride, CaF2?

Question

asked Oct 9, 2021 43.6k views

1 Answer

NingLee · Answer 1 · 2021-10-15T21:57:05+0000

CaF2: 40 + 19 x 2 = 78 g/mol
33.0g / 78 g/mol = 0.42 mol CaF2
Ca + F2 -> CaF2
0.42 mol
0.42 mol x 1/1 = 0.42 mol Ca
0.42 mol x 40 g/mol = 16.8 g Ca