Question

two bottles X and Y contain some water. from bottle X we pour into bottle Y twice as much water as bottle Y alredy contains. we then pour from bottle now contain 200 mL. How much water was in each bottle to start with?

Answer 1

To find the initial amount of water in each bottle, set up an equation and solve for the variables. The initial amount of water in bottle X is 133.33 mL and the initial amount of water in bottle Y is 66.67 mL.

Step-by-step explanation:

To solve this problem, we can set up an equation using the given information. Let's say the amount of water in bottle Y is 'y' mL. According to the problem, we pour twice as much water from bottle X into bottle Y. So, we pour 2y mL of water from bottle X into bottle Y. After pouring, bottle Y now contains 200 mL of water. This can be expressed as the equation: y + 2y = 200. Simplifying this equation, we get 3y = 200. Solving for y, we find that y = 66.67 mL. Therefore, the initial amount of water in bottle X was 2y = 133.33 mL and the initial amount of water in bottle Y was y = 66.67 mL.

Answer 2

Step-by-step explanation:

X had 300

Y had 100

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