Question

2. Using Charles’s Law solve the following: A sample of helium has a volume of 125 L at a temperature of 127 C, if the volume is decreased to 85.0 L what is the resulting temperature considering pressure does not change.

Answer 1

272.102K

Step-by-step explanation:

V1 = 125L

T1 = 127°C = (127 + 273.15)k = 400.15

V2 = 85L

T2 = ?

According to Charles law, the volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.

V = kT, k = V / T (where k = constant)

V1 / T1 = V2 / T2

125 / 400.15 = 85 / T2

400.15 * 85 = 125 * T2

34012.75 = 125T2

T2 = 34012.75 / 125

T2 = 272.102K

The resulting temperature is 272.102K