Question

A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume of 2.04 L and warmed to a temperature of 310 K. What is the final pressure of the gas in atmospheres (atm)?

Answer 1

Final pressure in (atm) (P1) = 6.642 atm

Step-by-step explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

`(PV)/(T) =(P1V1)/(T1) \\\\((784)(12.5))/(295) =((P1)(2.04))/(310)\\\\33.22 = ((P1)(2.04))/(310)\\\\P1=5,048.18877`

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm