Question

What is the empirical formula of the compound that is 25.3% magnesium and 74.7% chlorine

Answer 1

Answer:
`MgCl_2`

Step-by-step explanation:

25.3% Mg

74.7% Cl

First step: change % to g

25.3g Mg

74.7g Cl

Second step: calculate g/mol of each compound. You can do this by using the atomic mass.

`25.3gMg((1mol)/(24.30g))=1.04mol`

`74.7gCl((1mol)/(35.45g) )=2.11mol`

Third step: determine the lowest number and divide everything by it. Of the result, extract whole number only.

`Mg=(1.04)/(1.04) =1`

`Cl=(2.11)/(1.04)=2`

Fourth step: Write each compound with their respective number below.

This empirical formula should be:
`MgCl_2`