Answer:
A
Explanation:
A: (-2,1)
B: (3,0)
AB = sqrt[(1-0)² + (3--2)²]
AB = sqrt[1 + 25]
AB = sqrt(26)
sqrt(26)
Point A = (-2,1) and B = (3,0)
The distance is found by
d = sqrt( (x2-x1)^2 + (y2-y1) ^2)
= sqrt( ( 3 --2) ^2 + (0-1)^2)
= sqrt( ( 3 +2) ^2 + (0-1)^2)
= sqrt( 5^2 + (-1)^2)
= sqrt( 25+1)
= sqrt(26)
3.3m questions
4.2m answers