Answer:
55.5 seconds
Explanation:
The distance between the deer and bear is increasing at the rate of ...
(7 ft/s) +(3 ft/s) = 10 ft/s
The total distance apart we're interested in is ...
(185 yd)(3 ft/yd) = 555 ft
The time required to make a gap that large is ...
time = distance/speed = (555 ft)/(10 ft/s) = 55.5 s
It will be 55.5 seconds until the animals are 185 yards apart.