Question

If f(x)=4x^2 and g(x)=x+1, find (fog)(x)

Answer 1

Answer: The value of
`(f_\circ g)(x)` is
`4(x+1)^2` .

Explanation:

Given:
`f(x) = 4x^2 \text { and } g(x) = x+1`

To find:
`(f_\circ g)(x)`

As we know it is composition function which means that g(x) function is in f(x) function.

So we have

`(f_\circ g) (x) = f[g(x)]`

`\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2`

Now substitute the value of g(x) we get

`(f_\circ g)(x)= 4(x+1)^2`

Hence, the value of
`(f_\circ g)(x)` is
`4(x+1)^2` .