Answer:
a. The phenotype of the parents is that they have free earlobes
b. The genotype of the parents are Aa
c. The chance that their child would have free earlobes is 50%
Step-by-step explanation:
Heterozygous (different) = Aa
Homozygous (the same) = AA or aa
Make a punnett square for c.
A a
A AA Aa
a Aa aa