Question

the bow has a base area of 9/10 square foot and a height of 1/3 foot.How much packing material is required to fill the box

Answer 1

The amount of material to fill the box is: 0.3
`ft^3`

Explanation:

Recall that the volume (V) of a box is the product of the area of its base (B) times its height (H): V = B * H

Therefore, since in this case the area of the base is:

`B=(9)/(10) \,ft^2`

and the box's height is:

`H=(1)/(3) \,ft`

The total volume of the box (and what you need of material to fill it) is:

`V=B*H\\V=(9)/(10) \,\,ft^2*(1)/(3) \,ft\\V=(9*1)/(10*3) \,ft^3\\V=(3)/(10) \,ft^3\\V= 0.3\,\,t^3`