To solve this problem, firstly, let's find the width of the rectangle. The width of the rectangle is the horizontal distance between the upper-left and upper-right points. In the Cartesian coordinate system, this simply means taking the difference between the x-coordinates of these points. We find the difference between 4 (x-coordinate of upper-right point) and -4 (x-coordinate of upper-left point). This gives us 8 units, which is the width of our rectangle.
Now that we know the width, we can proceed to find the length. We know that the perimeter (total distance around the rectangle) is given by the formula 2L + 2W, where L is the length and W is the width of the rectangle.
We know that the perimeter is 20 units and the width is 8 units.
We can substitute these values into the formula and solve for L (the length):
20 = 2L + 2*8
Simplifying the right side gives us:
20 = 2L + 16,
Subtracting 16 from both sides gives us:
4 = 2L
Finally, divide both sides by 2 to solve for L:
L = 2 units.
So, the
Answer: width of the rectangle is 8 units and the length is 2 units.