Register
81p² + 5 = 41 how do I solve by square roots ​
168k views
4 votes
81p² + 5 = 41
how do I solve by square roots

​

User Mridula
by
7.4k points

1 Answer

3 votes

Answer:

p = ±
(2)/(3)

Explanation:

Given

81p² + 5 = 41 ( subtract 5 from both sides )

81p² = 36 ( divide both sides by 81 )

p² =
(36)/(81) ( take the square root of both sides )

p = ±
\sqrt{(36)/(81) }

= ±
(√(36) )/(√(81) ) = ±
(6)/(9) = ±
(2)/(3)

User Kieran Quinn
by
7.9k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.6m questions

11.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair and a desk for $77. Find the price of a chair, table, and of a desk.
Link Copied!