Question

HELLPPP ME PLEASEE!!!!!!

PLEASE AND THANK YOU!!!

Answer 1

15 children and 5 adults

Explanation:

Lets call the adults 'a' and the children 'c'.

We know that 20 tickets by a family was purchased so a + c = 20.

We also know that the total cost of the tickets was $100 and one adult ticket cost $8 and one child cost $4 so 8a + 4c = 100

Now we have simultaneous equations,

α) a + c = 20

β) 8a + 4c = 100

→ Multiply α) by 8 to make the same 'a' coefficient

α) 8a + 8c = 160

β) 8a + 4c = 100

→ Minus the α) from β)

4c = 60

→ Divide both sides by 4 to work out how many child tickets were bought

c = 15

→ Substitute the value of c = 15 back into the equation of a + c = 20

a + 15 = 20

→ Minus 15 from both sides to work out how many adult tickets were bought

a = 5

Answer 2

So there are 20 people in the family.
The total cost of the tickets were $100. Tickets for adults cost $8 and children cost $4.
To find the answer for the number of adults you need to divide the $100 by $8 and do the same for children but divide the $100 by $4.
So 5 of the family members were adults and 15 were children.
5 adults = $40
15 children = $ 60