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25 votes
25 votes
NO LINKS!! Please help​

NO LINKS!! Please help​-example-1
User Mesmin
by
2.8k points

2 Answers

21 votes
21 votes

Answer:

FJ = 32

IJ = 24

FG = 48

Explanation:

Getting Started with FG


(IH)/(AB) =(FG)/(ED)


(72)/(36) =(FG)/(24)


(FG)/(24) =2


FG=24(2)=48

The proportion between polygons is 2:1


IJ=2CB


IJ=2(12)=24


FJ=2BC=2(16)=32

Hope this helps

User Marcopah
by
3.3k points
18 votes
18 votes

Answer:

FJ = 32

IJ = 24

FG = 48

Explanation:

Given: HGFJI ~ AEDCB

From inspection of the diagram, the corresponding sides are:

HG~AE

FG~DE

FJ~DC

IJ~CB

IH~BA

The only pair of sides that both have side lengths are IH and BA. Therefore, we can use these to figure out the scale factor of dilation.

IH = 72 and BA = 36

⇒ IH/BA= 72/36 = 2

Therefore, HGFJI is an enlargement of AEDCB by a scale factor of 2

If HG = 56

⇒ AE = 56 ÷ 2 = 28

If DE = 24

⇒ FG = 24 × 2 = 48

If DC = 16

⇒ FJ = 16 × 2 = 32

If CB = 12

⇒ IJ = 12 × 2 = 24

User Jonas Wolf
by
2.7k points