What is the equation of the line that passes through the point (-2,-8) and has a slope of 11?

asked Feb 12, 2023 83.1k views

9 votes

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6 votes

Answer:

y = 11x +14

Explanation:

The work:

y-y_(0) =m(x-x_(0) )

$x_(0) =-2\\y_(0) =-8\\m=11$

y-(-8)=11(x-(-2))

y+8=11(x+2)

y=11x+22-8

The equation:

y=11x+14

Hope this helps

John Alexiou answered Feb 16, 2023

5.0k points

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