Question

What is the equation of the line that passes through the point (-2,-8) and has a slope of 11?

Answer 1

y = 11x +14

Explanation:

The work:

`y-y_(0) =m(x-x_(0) )`

`x_(0) =-2\\y_(0) =-8\\m=11`

`y-(-8)=11(x-(-2))`

`y+8=11(x+2)`

`y=11x+22-8`

The equation:

`y=11x+14`

Hope this helps