Question

P

41,840 J of heat is applied to a sample of water raising its temperature from 22°C to 28.5°C. What is the sample of water's mass?
m= 476.3 g
O AT= 6.5 °C
m= 1222.4 g
m= 1538.5 g

Answer 1

m = 1538.5 g

Step-by-step explanation:

To answer this question, use the equation for specific heat:

`q=mc \Delta T`

Where q is the total heat energy, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the temperature change.

You will be expected to know the specific heat of water, which is 4.186 J/g/C. Using the information in the question:

`41840=m(4.186)(28.5-22)\\41840=27.2m\\m=1538.2`

The final answer, 1538.5 g, is closest.