Question

A golfball is hit from ground level with an initial vertical velocity of 80 ft/s. Use the function h(t) = −16t2 + v0t + h0, where h(t) is the height of a golfball hit with initial vertical velocity v0 from initial height h0 after t seconds in the air, to find the time at which the golfball will hit the ground.

Answer 1

Explanation:

ball is hit from the ground level i.e h0=0

initial velocity=80

when the ball hits the ground it's height from the ground=0

substitute the data in the above function

0=-16t^2+80×t+0

t=0 is a solution but it is at the beginning of the projection

16t=80

t=5