142k views
14 votes
NO LINKS!! Please help​

NO LINKS!! Please help​-example-1
User Gmsantos
by
8.1k points

2 Answers

1 vote

Answer:

FJ = 32

IJ = 24

FG = 48

Explanation:

Getting Started with FG


(IH)/(AB) =(FG)/(ED)


(72)/(36) =(FG)/(24)


(FG)/(24) =2


FG=24(2)=48

The proportion between polygons is 2:1


IJ=2CB


IJ=2(12)=24


FJ=2BC=2(16)=32

Hope this helps

User Shrinath
by
8.3k points
7 votes

Answer:

FJ = 32

IJ = 24

FG = 48

Explanation:

Given: HGFJI ~ AEDCB

From inspection of the diagram, the corresponding sides are:

HG~AE

FG~DE

FJ~DC

IJ~CB

IH~BA

The only pair of sides that both have side lengths are IH and BA. Therefore, we can use these to figure out the scale factor of dilation.

IH = 72 and BA = 36

⇒ IH/BA= 72/36 = 2

Therefore, HGFJI is an enlargement of AEDCB by a scale factor of 2

If HG = 56

⇒ AE = 56 ÷ 2 = 28

If DE = 24

⇒ FG = 24 × 2 = 48

If DC = 16

⇒ FJ = 16 × 2 = 32

If CB = 12

⇒ IJ = 12 × 2 = 24

User Penanghill
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories