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Find the magnitude of the horizontal and vertical components of a velocity of 23 MPH at an angle of 16 degrees with the ground.

Find the magnitude of the horizontal and vertical components of a velocity of 23 MPH-example-1

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Answer:

Option C : Horizontal component 22MPH, Vertical component, 6MPH

Explanation:

The magnitude of the horizontal components is calculated as

|Vx| = 23MPH × Cos 16°

|Vx| = 22.109019007MPH

Therefore, approximately to the nearest whole number,

|Vx| = 22MPH

The magnitude of the Vertical component is calculated as

|Vy| = 23MPH × Sin 16°

|Vy| = 6.3396591838MPH

Therefore, approximately to the nearest whole number,

|Vy| = 6MPH

Therefore, the magnitude of the horizontal component is 22MPH and vertical component is 6MPH of a velocity of 23 MPH at an angle of 16 degrees with the ground.

User Reinaldoluckman
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