Question

Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4

Given that 61µg of aluminum phosphate precipitate formed, calculate the micromoles of aluminum ions in 50 mL of river water. (1µg = 1 x 10^(-6)g)

Answer 1

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

• 27+31+16(4)
• 58+48
• 106u

Moles of AlPO_4

• 61µg/106
• 0.000061/106
• 5.75×10^{-7}
• 57.5µmol

Moles of Al3+=57.5µmol