Answer:
For the total budget not to exceed $230,000 the distance from town A to the power plant should be 147.5 miles
Explanation:
We are given the cost of connection of power to a town as $1,000.00 per mile of cable
Location of the towns as
A = 30 miles West of B
C = 85 miles East of B
C = 100 miles west of D
Therefore let the location of the power station be Z such that the total cost of supplying power to the four towns = $230,000
And let the distances of the town from the power station be
Z - A = a miles
Z - B = b miles
Z - C = c miles and
Z - D = d miles
Therefore, (a + b + c + d) × 1000 = $230,000
Hence, (a + b + c + d) = 230 miles
Since the towns are;
A = Start
B = 30 miles
C = 115 miles
D = 215 miles
4·Z - (A + B + C + D) = 230 where A = 0
4·Z - (B + C + D) = 230
4·Z - (30 + 115 + 215) = 230
4·Z = 230 + 360 = 590
Z = 147.5 miles
The location of the power plant should be at 147.5 miles from town A.