Answer:
P(z ≤ -2.263) = 0.012 ( 3 dp)
Yes, the computer store has been given laptops of lower than average quality. The probability is unlikely to have occurred by chance.
Explanation:
Sample size, n = 32
Mean,
Standard deviation,
Sample mean,
z = - 2.263
Probability that the selected laptops will have a mean replacement time of 4.3 years or less.
P(M ≤ 4.3 years) = P(z ≤ -2.263)
P(z ≤ -2.263) = 0.0118
P(z ≤ -2.263) = 0.012 ( 3 dp)
P(z ≤ -2.263) = 0.012 is less than 0.05 significant level, it is safe to conclude that the computer store has been given laptops of lower than average quality