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Air enters the compressor of a cold air-standard Brayton cycle with regeneration at 100 kPa, 300 K, with a volume flow rate of 5 m3/s. The compressor pressure ratio is 13, and the turbine inlet temperature is 1400 K. The turbine and compressor each have isentropic efficiencies of 80% and the regenerator effectiveness is 80%. For the air, k = 1.4 and the ambient temperature is T0 = 300 K.Calculate

a) Thermal efficiency for the cycle
b) Back work ratio
c) Net power
d) Rate of exergy destruction in the regenerator for t0=300K

User John Kears
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1 Answer

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Answer:

a) nth = 0.2541 = 25.41%

b) B.W.R = 0.6464

c) Pnet = 1151.73 kw

d) 206.38 kw

In turbine: energy destruction = 300 x 1.027 = 308.1 kw

Step-by-step explanation:

See attached images

Air enters the compressor of a cold air-standard Brayton cycle with regeneration at-example-1
Air enters the compressor of a cold air-standard Brayton cycle with regeneration at-example-2
Air enters the compressor of a cold air-standard Brayton cycle with regeneration at-example-3
Air enters the compressor of a cold air-standard Brayton cycle with regeneration at-example-4
Air enters the compressor of a cold air-standard Brayton cycle with regeneration at-example-5
User AKhooli
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