Question

Balance the following equation and answer the question. ___CuCl + ___ H2S ------ ___ Cu2S + ___ HCl If 1.2 moles of CuCl is mixed with an excess of H2S gas, how many moles of Cu2S would be made? *

Answer 1

A. 2CuCl + H2S —> Cu2S + 2HCl

B. 0.6 mole of Cu2S

Step-by-step explanation:

A. The balancing equation.

The equation can be balance as follow:

CuCl + H2S —> Cu2S + HCl

There are 2 atoms of Cu on the right side and 1 atom on the left. It can be balance by putting 2 in front of CuCl as shown below:

2CuCl + H2S —> Cu2S + HCl

There are 2 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 2 in front of HCl as shown below:

2CuCl + H2S —> Cu2S + 2HCl

Now we can see that the equation is balanced.

B. Determination of the number of mole of Cu2S produced by the reaction 1.2 mole of CuCl.

This is illustrated below:

2CuCl + H2S —> Cu2S + 2HCl

From the balanced equation above, 2 moles of CuCl reacted to produce 1 mole of Cu2S.

Therefore, 1.2 mole of CuCl will react to produce = 1.2/2 = 0.6 mole of Cu2S.

Therefore, 0.6 mole of Cu2S is produced from the reaction of 1.2 mole of CuCl.